Question

Phân tích đa thức thành nhân tử: a⁵+a+1

Answer 1

a⁵+a+1=a⁵+a⁴+a³+a²+a+1-a⁴-a³-a²

=a³.(a²+a+1)+(a²+a+1)-a².(a²+a+1)

=(a²+a+1)(a³-a²+1)

Answer 2

Ta có : \(a^5+a+1=\left(a^5-a^2\right)+\left(a^2+a+1\right)\)

\(=a^2\left(a^3-1\right)+\left(a^2+a+1\right)\)

\(=a^2\left(a-1\right)\left(a^2+a+1\right)+\left(a^2+a+1\right)\)

\(=\left(a^2+a+1\right)\left(a^3-a^2+1\right)\)

Answer 3

\(a^5+a+1=a^5+a^4+a^3+a^2+a+1-a^4-a^3-a^2\)

\(=a^2\left(a^3-1\right)+\left(a^2+a+1\right)\)

\(=a^2\left(a-1\right)\left(a^2+a+1\right)+\left(a^2+a+1\right)\)

\(=\left(a^2+a+1\right)\left(a^3-a^2+1\right)\)

Chúc bạn học tốt 

Answer 4

Trong h cg~ có