Question

Phân tích đa thức thành nhân tử: 
a) x(x+y)-5x-5y
b) 3x-5y-6ax+10ay
c) a²-6a-b²+6b
d) 100a²-20a-2b-b²
e) 36x²-12x+1-b²
f)  x²-z²+y²-2xy

Answer 1

a,x(x+y)-5x-5y

=x(x+y)-5(x+y)

=(x+y)(x-5)

b,3x-5y-6ax+10ay

=(3x-6ax)-(5y-10ay)

=3x(1-2a)-5y(1-2a)

=(1-2a)(3x-5y)

c,a²-6a-b²+6b

=(a²-b²)-(6a-6b)

=(a-b)(a+b)-6(a-b)

=(a-b)(a+b-6)

d,100a²-20a-2b-b²

=(100a²-b²)-(20a+2b)

=(10a-b)(10a+b)-2(10a+b)

=(10a+b)(10a-b-2)

e,36x²-12x+1-b²

=(36x²-12x+1)-b²

=(6x-1)²-b²

=(6x-1-b)(6x-1+b)

f,x²-z²+y²-2xy

=(x²-2xy+y²)-z²

=(x-y)²-z²

=(x-y-z)(x-y+z)