Question

Phân tích đa thức thành nhân tử A) x³-2x² B) y²+2y-x²+1 C) (x+1)²-25

Answer 1

a,\(A=x^3-2x^2=x^2\left(x-2\right)\)

\(b,\) \(y^2+2y-x^2+1=-x^2-xy-x+xy+y^2+y+x+y+1\)

\(=-x\left(x+y+1\right)+y\left(x+y+1\right)+\left(x+y+1\right)\)

\(=\left(-x+y+1\right)\left(x+y+1\right)\)

\(c,\) \(\left(x+1\right)^2-25=\left(x+1+5\right)\left(x+1-5\right)=\left(x+6\right)\left(x-4\right)\)

Answer 2

Answer 3

a,x³−2x²=x²(x−2)

b,y²+2y-x²+1=(y+1)²-x²=(y+x+1)(y-+x+1)

c, (x+1)²−25=(x+1+5)(x+1−5)=(x+6)(x−4)