\(2x-3x^2+x\)
\(=x\left(2-3x+1\right)\)
\(=x\left(-3x+3\right)\)
\(=-3x\left(x-1\right)\)
2x - 3x2 + x
=x.(2-3x+1)
=x.(3-3x)
=x.(3.(1-x))
=3x.(1-x)
2x - 3x2 + x
=x.(2-3x+1)
=x.(3-3x)
=x.(3.(1-x))
=3x.(1-x)
2x - 3x2 + x
=x.(2-3x+1)
=x.(3-3x)
=x.(3.(1-x))
=3x.(1-x)
\(2x-3x^2+x=x\left(2-3x+1\right)=x\left(-3x+3\right)=-3x\left(x-1\right)=3x\left(1-x\right)\)
Ta có : 2x-3x2+x
=x(2-3x+1)
=x(3-3x)
=3x(1-x)
\(\)2x-3x2+x=x.(2-3x+1)
=x.(3-3x)
=3x.(1-x)