Question

Phân tích đa thức thành nhân tử :

27x³ - 27x² + 18x - 4

Answer 1

\(27x^3-27x^2+18x-4\)

\(=27x^3-18x^2+12x-9x^2+6x-4\)

\(=3x\left(9x^2-6x+4\right)-\left(9x^2-6x+4\right)\)

\(=\left(3x-1\right)\left(9x^2-6x+4\right)\)

Answer 2

27x³ - 27x² + 18x - 4

= 27x³ - 9x² - 18x² + 6x + 12x - 4

= 9x² ( 3x - 1 ) - 6x ( 3x - 1 ) + 4 ( 3x - 1 )

= ( 9x² - 6x + 4 ) ( 3x - 1 )

Answer 3

\(27x^3-27x^2+18x-4\)

\(=27^3-18x^3+12x-9x^2+6x-4\)

\(=3x\left(9x^2-6x+4\right)-\left(9x^2-6x+4\right)\)

\(=\left(3x-1\right)\left(9x^2-6x+4\right)\)