Question

OXI cua nguyen to R chua ro hoa tri co chua 47,06 %ve khoi luong la oxi .Nguyen to do la

a,Fe        b, Cr          c, Al            d, N  

Answer 1

CT : R₂O_n

\(\%O=\dfrac{16n}{2R+16n}\cdot100\%=47.06\%\)

\(\Leftrightarrow2R+16n=34n\)

\(\Leftrightarrow R=9n\)

\(BL:n=3\Rightarrow R=27\)

=> C