`\int [x^2-x+4]/[x^3-3x+2x] dx``=\int [x^2-x+4]/[x(x-1)(x-2)] dx``=\int (2/x-4/[x-1]+3/[x-2]) dx``=2ln|x|-4ln|x-1|+3ln|x-2|+C`.Câu trả lời: `\int [x^2-x+4]/[x^3-3x+2x] dx``=\int [x^2-x+4]/[x(x-1)(x-2)] dx``=\int (2/x-4/[x-1]+3/[x-2]) dx``=2ln|x|-4ln|x-1|+3ln|x-2|+C`.