\(\left(n+1\right)\left(2+n\right)\left(n^2+1\right)=\left(2+n^2+2+n\right)\left(n^2+1\right)\)
\(=\left(n^2+n+4\right)\left(n^2+1\right)=n^4+n^2+n^3+n+4n^2+4\)
\(=n^4+5n^2+n^3+n+4\)
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(n+1)(2+n)(n2+1)=(2+n2+2+n)(n2+1)(n+1)(2+n)(n2+1)=(2+n2+2+n)(n2+1)
=(n2+n+4)(n2+1)=n4+n2+n3+n+4n2+4=(n2+n+4)(n2+1)=n4+n2+n3+n+4n2+4
=n4+5n2+n3+n+4
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