\(b,=-\dfrac{5}{9}\cdot\dfrac{3}{7}-\dfrac{4}{9}\cdot\dfrac{3}{7}=\dfrac{3}{7}\left(-\dfrac{5}{9}-\dfrac{4}{9}\right)=-\dfrac{3}{7}\\ c,=\left(\dfrac{1}{12}\right)^2-\dfrac{3}{8}=\dfrac{1}{144}-\dfrac{3}{8}=-\dfrac{53}{144}\)
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