Question

Mọi người giúp mình với

Answer 1

\(a,=\left(-\dfrac{5}{11}\right)\left(\dfrac{2}{9}+\dfrac{7}{9}-1\right)=-\dfrac{5}{11}\cdot0=0\\ b,=-\dfrac{4}{9}-\dfrac{5}{9}+2,568-1=-2+2,568=0,568\\ c,=\dfrac{1}{3}+\left(\dfrac{12}{67}-\dfrac{79}{67}\right)+\left(\dfrac{13}{41}+\dfrac{28}{41}\right)=\dfrac{1}{3}-1+1=\dfrac{1}{3}\\ d,=\dfrac{96}{7}\cdot\dfrac{3}{2}-\dfrac{86}{7}\cdot\dfrac{3}{2}=\dfrac{3}{2}\left(\dfrac{96}{7}-\dfrac{86}{7}\right)=\dfrac{3}{2}\cdot\dfrac{10}{7}=\dfrac{15}{7}\)