\(\Leftrightarrow\dfrac{x\left(x+2\right)+x-2-8}{x\left(x-2\right)}=0\) \(\left(đk:x\ne0,2\right)\)
\(\Leftrightarrow x^2+2x+x-2-8=0\)
\(\Leftrightarrow x^2+3x-10=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}x_1=2\left(l\right)\\x_2=-5\left(n\right)\end{matrix}\right.\)
Vậy \(S=\left\{-5\right\}\)
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