c)
`2x-(3-5x)=4(x+3)`
`<=> 2x-3+5x=4x+12`
`<=> 2x+5x-4x=12+3`
`<=> 3x=15`
`<=> x=5`
d)
\(\dfrac{2x+3}{3}=\dfrac{5-4x}{2}\\ < =>\left(2x+3\right)\cdot2=\left(5-4x\right)\cdot3\\ < =>4x+6=15-12x\\ < =>4x+12x=15-6\\ < =>16x=9\\ < =>x=\dfrac{9}{16}\)
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