\(a,\dfrac{10}{11}+\dfrac{3}{11}:3-\dfrac{1}{7}=\dfrac{10}{11}+\dfrac{3}{11}.\dfrac{1}{3}-\dfrac{1}{7}=\dfrac{10}{11}+\dfrac{1}{11}-\dfrac{1}{7}=1-\dfrac{1}{7}=\dfrac{6}{7}\\ b,\dfrac{-3}{7}+\dfrac{5}{13}+\dfrac{3}{7}=\left(\dfrac{-3}{7}+\dfrac{3}{7}\right)+\dfrac{5}{13}=\dfrac{5}{13}\\ c,-\dfrac{3}{13}+\dfrac{7}{12}-\dfrac{10}{13}+\dfrac{5}{12}=\left(-\dfrac{3}{13}-\dfrac{10}{13}\right)+\left(\dfrac{7}{12}+\dfrac{5}{12}\right)=\left(-1\right)+1=0\)
\(d,\dfrac{5}{3}.\dfrac{7}{25}+\dfrac{5}{3}.\dfrac{21}{25}-\dfrac{5}{3}.\dfrac{7}{25}=\left(\dfrac{5}{3}.\dfrac{7}{25}-\dfrac{5}{3}.\dfrac{7}{25}\right)+\dfrac{5}{3}.\dfrac{3.7}{5.5}=\dfrac{7}{5}\)
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