\(a,=\left(-\dfrac{5}{4}\right)\left(35\dfrac{1}{6}-45\dfrac{1}{6}\right)=\left(-\dfrac{5}{4}\right)\left(-10\dfrac{1}{6}\right)=\dfrac{5}{4}\cdot\dfrac{61}{6}=\dfrac{305}{24}\\ b,=25\left(-\dfrac{1}{125}\right)-\dfrac{1}{2}+\dfrac{1}{5}=-\dfrac{1}{5}-\dfrac{1}{2}+\dfrac{1}{5}=-\dfrac{1}{2}\)
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