M = 15.2 = 30(g/mol)\(m_C=\dfrac{80.30}{100}=24\left(g\right)=>n_C=\dfrac{24}{12}=2\left(mol\right)\)\(m_H=\dfrac{20.30}{100}=6\left(g\right)=>n_H=\dfrac{6}{1}=6\left(mol\right)\)=> CTHH: C2H6=> DCâu trả lời: M = 15.2 = 30(g/mol)\(m_C=\dfrac{80.30}{100}=24\left(g\right)=>n_C=\dfrac{24}{12}=2\left(mol\right)\)\(m_H=\dfrac{20.30}{100}=6\left(g\right)=>n_H=\dfrac{6}{1}=6\left(mol\right)\)=> CTHH: C2H6=> D