\(\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\dfrac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\dfrac{4}{15}\right|=-2,15+3,15\)
\(\left|x+\dfrac{4}{15}\right|=1,6=\dfrac{8}{5}\)
`=>`\(\left[{}\begin{matrix}x+\dfrac{4}{15}=\dfrac{8}{5}\\x+\dfrac{4}{15}=-\dfrac{8}{5}\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=\dfrac{8}{5}-\dfrac{4}{15}=\dfrac{4}{3}\\x=-\dfrac{8}{5}-\dfrac{4}{15}=-\dfrac{28}{15}\end{matrix}\right.\)
`=>`\(x\in\left\{\dfrac{4}{3};-\dfrac{28}{15}\right\}\)
\(\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\dfrac{4}{15}\right|+3,75=2,15\)
\(\left|x+\dfrac{4}{15}\right|=2,15-3,75\)
\(\left|x+\dfrac{4}{15}\right|=-\dfrac{8}{5}\)
\(\Rightarrow x+\dfrac{4}{15}=-\dfrac{8}{5}\)
\(x=-\dfrac{8}{5}-\dfrac{4}{15}\)
Vậy \(x=-\dfrac{28}{15}\)