Question

\(\left|x^2-4\right|+\left(x+2\right)^2=0\)

Answer 1

Dấu ''='' xảy ra khi 

\(\left\{{}\begin{matrix}\left|x^2-4\right|=0\\\left(x+2\right)^2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\\x=-2\end{matrix}\right.\Leftrightarrow x=-2\)