Ta có : (x - 3)2016 \(\ge0\left(\forall x\right)\)
(y - 4)2018 \(\ge0\left(\forall x\right)\)
Mà (x - 3)2016 + (y - 4)2018 = 0
Suy ra : \(\hept{\begin{cases}\left(x-3\right)^{2016}=0\\\left(y-4\right)^{2018}=0\end{cases}}\)
<=> \(\hept{\begin{cases}x-3=0\Rightarrow x=3\\y-4=0\Rightarrow y=4\end{cases}}\)
a, \(\left[x+1\right]^2+\left|y+1\right|=0\)
b, \(\left|x+7\right|+\left[y-2\right]^{2016}=0\)
Tìm x, biết:
a) \(\left|x-24\right|+\left|y+8\right|=1\)
b)\(\left(x-2\right)^{10}+\left|y-2\right|=0\)
c)\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+30\right)=1240\)
d)\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+2017+2018=2018\)
Giải thích cụ thể giúp mk nha
Tìm x,y,x biết :
\(a,2018=|x-2016|+|x-2014|\)
\(b,\left(x-3\right)^x-\left(x-3\right)^{x+2}=0\)
giúp mình với các bn ơi mai mình nộp rồi
mình sẽ k cho
Tìm x,y biết:
\(\left|x+\frac{11}{7}\right|+\left|x+\frac{2}{7}\right|+\left|x+\frac{4}{7}\right|=4x\)
\(\left(x-2\right)^{2014}+\left(y-1\right)^{2016}+\left(x-y-2\right)=0\)
mk đang cần gấp giúp mk nha các bn
\(\left(x-5\right)^{2016}=\left(x-5\right)^{2018}\)
cho \(x,y\ne0\)thỏa mãn\(x^{2015}+x^{2015}=x^{2016}+x^{2016}=x^{2017}+x^{2017}\)
tính \(S=2018.\left(x^{2018}+y^{2018}\right)\)
Tìm x, y thỏa \(\left(2x-y+7\right)^{2018}+\left(\left|x-3\right|\right)^{2019}\le0\)
Tim X:Y biet
\(\left(x-1\right)^2+\left(y-4\right)^2=0\)
Tìm x \(\in\)Z sao cho \(\left(x-1\right)^{2016}=\left(1-x\right)^{2018}\)
