Question

\(\left(x-1\right)^6=\left(x-1\right)^8\)

b) \(\left(2x+1\right)^4=\left(2x+1\right)^8\)

Answer 1

a/ (x - 1)⁶ = (x - 1)⁸

=> (x - 1)⁶ [1 - (x - 1)²] = 0

=> (x - 1)⁶ (1 - x² + 2x - 1) = 0

=> (x - 1)⁶ (-x² + 2x) = 0

=> x - 1 = 0 => x = 1

hoặc - x² + 2x = 0 => x = 0 hoặc x = 2

                               Vậy x = 0, x = 1, x = 2