\(\frac{\left[\left(6\frac{3}{5}-3\frac{3}{14}\right)\cdot5\frac{5}{6}\right]}{\left(21-1,25\right):2,5}\)
Đặt 2 biểu thức trên là A và B
Ta có : \(A=\left[\left(6\frac{3}{5}-3\frac{3}{14}\right)\cdot5\frac{5}{6}\right]\)
\(A=\left[\left(\frac{33}{5}-\frac{45}{14}\right)\cdot\frac{35}{6}\right]\)
\(A=\left[\frac{237}{70}\cdot\frac{35}{6}\right]=\frac{79}{4}\)
Vậy A = 79/4
\(B=\left[\left(21-1,25\right):2,5\right]\)
\(B=\left[\left(21-\frac{5}{4}\right):\frac{5}{2}\right]\)
\(B=\frac{79}{4}:\frac{5}{2}=\frac{79}{4}\cdot\frac{2}{5}=\frac{79}{10}\)
Vậy B = 79/10
Do đó \(\frac{A}{B}=\frac{\frac{79}{4}}{\frac{79}{10}}=\frac{79}{4}\cdot\frac{10}{79}=\frac{10}{4}=\frac{5}{2}\)
mk cảm ơn bn nhìu
[(33/5-45/14.)35/6]:[(21-1,25):2,5]
[237/70.35/6]:[(21-1/25):2,5]
79/4:[(21-1,25):2,5]
79/4:[19,75:2,5]
79/4:79/10
79/4.10/79
5/2
