Question

\(\left(\frac{\sqrt{3}}{\sqrt{2}}+\sqrt{3}\right)-\sqrt{6}\)= ?

Answer 1

\(\left(\frac{\sqrt{3}}{\sqrt{2}}+\sqrt{3}\right)-\sqrt{6}=\left(\frac{\sqrt{6}}{\sqrt{2}}+\sqrt{3}\right)-\sqrt{6}=\frac{\sqrt{6}+2\sqrt{3}}{2}-\sqrt{6}=\frac{-\sqrt{6}+2\sqrt{3}}{2}\)