Question

\(\left(\frac{1}{2}-1\right).\left(\frac{1}{3}-1\right).\left(\frac{1}{4}-1\right).....\left(\frac{1}{2003}-1\right)\)giup mik giải câu này:)

Answer 1

(1/2-1)(1/3-1)(1/4-1)...(1/2003-1)

=(-1)/2.(-2)/3.(-3)/4....(-2002)/2003

=\(\frac{\left(-1\right).\left(-2\right).\left(-3\right)...\left(-2002\right)}{2.3.4....2003}=-\frac{1}{2003}\)

Answer 2

= (-1/2).(-2/3).(-3/4).....(-2002/2003) (Có 2002 p/số)

= (-1).(-2).(-3)....(-2002) / (2.3.4.....2003)

= 2.3.4....2002 / 2.3.4....2002.2003

= 1/2003