Question

\(\left[\dfrac{\left(x-1\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)^2}\right]:\left[\dfrac{\left(x+2\right)\left(x+1\right)-2}{\left(x-1\right)\left(x+1\right)\left(x+2\right)}\right]\)

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Answer 1

Lời giải:

Đặt biểu thức trên là $A$ thì:

\(A=\frac{1}{x+1}:\frac{x^2+3x+2-2}{(x-1)(x+1)(x+2)}=\frac{1}{x+1}:\frac{x(x+3)}{(x-1)(x+1)(x+2)}\)

\(=\frac{1}{x+1}.\frac{(x-1)(x+1)(x+2)}{x(x+3)}=\frac{(x-1)(x+2)}{x(x+3)}\)