Question

\(\left(2x+1\right)^4=\left(2x+1\right)^6\)

Tim x

Answer 1

\(\left(2x+1\right)^4=\left(2x+1\right)^6\)

\(\Rightarrow\left(2x+1\right)^4=\left(2x+1\right)^4.\left(2x+1\right)^2\)

\(\Rightarrow\left(2x+1\right)^2=\left(2x+1\right)^4:\left(2x+1\right)^4\)

\(\Rightarrow\left(2x+1\right)^2=1\)

\(\Rightarrow\left(2x+1\right)^2=1^2\)

\(\Rightarrow2x+1=1\)

\(\Rightarrow2x=0\)

\(\Rightarrow x=0\)

Vậy \(x=0\)

Answer 2

\(\left(2x+1\right)^4\)\(=\left(2x+1\right)^6\)

\(\Rightarrow\left(2x+1\right)^4\)\(=\left(2x+1\right)^4\)\(.\left(2x+1\right)^2\)

\(\Rightarrow\left(2x+1\right)^2\)\(=\left(2x+1\right)^4\)\(:\left(2x+1\right)^4\)

\(\Rightarrow\)\(\left(2x+1\right)^2\)\(=1^2\)

\(\Rightarrow\)\(2x+1=1\)

\(\Rightarrow2x=0\)

\(\Rightarrow x=0\)

Answer 3

\(\left(2x+1\right)^4=\left(2x+1\right)^6\)

\(\Rightarrow\left(2x+1\right)^4=\left(2x+1\right)^4.\left(2x+1\right)^2\)

\(\Rightarrow\left(2x+1\right)^2=\left(2x+1\right)^4:\left(2x+1\right)^4\)

\(\Rightarrow\left(2x+1\right)^2=1\)

\(\Rightarrow\left(2x+1\right)^2=1^2\)

\(\Rightarrow2x+1=1\)

\(\Rightarrow2x=0\)

\(\Rightarrow x=0\)

Answer 4

giải thiếu 1 trường họp

Answer 5

( 2x + 1) 4 = ( 2x + 1) 6

suy ra ( 2x + 1 ) 4 = ( 2x + 1 ) 4. ( 2x + 1) 2

suy ra ( 2x + 1) 2 = ( 2x + 1 ) 4 : ( 2x +1) 4

suy ra ( 2x +1 ) 2 = 12

suy ra 2x+1=1

suy ra 2x = 0 

suy ra x = 0

Answer 6

(2x+1)⁴ = (2x+1)⁶ => 2x+1=0 (không thể xảy ra) hoặc 2x+1=1

=> x=0