\(\text{Đ}\text{ặt}\text{ }A=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)
\(\Rightarrow3A=3+1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\)
\(\Rightarrow3A-A=3-\frac{1}{81}\)
\(\Rightarrow2A=\frac{242}{81}\)
\(\Rightarrow A=\frac{242}{81}:2=\frac{121}{81}\)