Question

Kết quả của tích 6xy( 1/2 x^2y - 1/3 x^3y^ 2 - 1) 

Answer 1

\(6xy\left(\dfrac{1}{2}x^2y-\dfrac{1}{3}x^3y^2-1\right)\)

\(=6xy\cdot\dfrac{1}{2}x^2y+6xy\cdot\left(-\dfrac{1}{3}x^3y^2\right)+6xy\cdot\left(-1\right)\)

\(=3x^3y^2-2x^4y^3-6xy\)

Answer 2

\(6xy\left(\dfrac{1}{2x^2y}-\dfrac{1}{3x^3y^2}-1\right)\)

\(=\dfrac{3}{x}-\dfrac{2}{x^2y}-6xy\)