\(\overline{A}=\dfrac{39.93,258+40.0,012+41.6,73}{100}=39,13472\)
=> \(\dfrac{0,69}{39,13472}\left(mol\right)\le n_K\le\dfrac{0,986}{39,13472}\left(mol\right)\)
=> \(17,63\left(mmol\right)\le n_K\le25,2\left(mmol\right)\)
=> \(\dfrac{17,63}{5}\left(mmol/l\right)\le C_K\le\dfrac{25,2}{5}\left(mmol/l\right)\)
=> 3,526 (mmol/l) \(\le C_K\le5,04\left(mmol/l\right)\)