Question

hon so -7/1/3+5/3/7=

tinh bang 2 cach

Answer 1

\(C1:-7\frac{1}{3}+5\frac{3}{7}=\frac{-20}{3}+\frac{38}{7}\)

\(=\frac{-140}{21}+\frac{114}{21}=\frac{-26}{21}\)

\(C2:-7\frac{1}{3}+5\frac{3}{7}=\left(5-7\right)+\left(\frac{1}{3}+\frac{3}{7}\right)\)

\(=-2+\frac{16}{21}=\frac{-26}{21}\)

Vậy \(-7\frac{1}{3}+5\frac{3}{7}=\frac{-26}{21}\)