Gọi công thức chung của 2 khí là RO2 \(\Rightarrow\overline{M}_{RO_2}=28\cdot2=56\)
Ta có: \(\left\{{}\begin{matrix}n_{RO_2}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\\n_{OH^-}=0,1\cdot1,2+0,1\cdot0,8=0,2\left(mol\right)\end{matrix}\right.\) \(\Rightarrow\) Tạo 2 loại muối
PT ion: \(RO_2+OH^-\rightarrow HRO_3^-\)
a_____a_________a (mol)
\(RO_2+2OH^-\rightarrow RO_3^{2-}+H_2O\)
b_____2b________b (mol)
Ta lập HPT: \(\left\{{}\begin{matrix}a+b=0,15\\a+2b=0,2\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}a=0,1\\b=0,05\end{matrix}\right.\)
Bảo toàn nguyên tố: \(\left\{{}\begin{matrix}n_{Na^+}=n_{NaOH}=0,1\cdot1,2=0,12\left(mol\right)\\n_{K^+}=n_{KOH}=0,1\cdot0,8=0,08\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow m_{muối}=m_{Na^+}+m_{K^+}+m_{RCO_3^-}+m_{RO_3^{2-}}=21,58\left(g\right)\)