\(Mg+2HCl\rightarrow MgCl_2+H_2\)
x_____2x_______ x ______ x
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
x ____ 2y_____ y ______ y
Giải hệ phương trình :
\(\left\{{}\begin{matrix}24x+65y=22,6\\x+y=\frac{13,44}{22,4}\end{matrix}\right.\rightarrow\left\{{}\begin{matrix}x=0,4\\y=0,2\end{matrix}\right.\)
\(\%m_{Mg}=\frac{0,4.24}{22,6}.100\%=42,48\%;\%m_{Zn}=100\%-42,48\%=57,52\%\)
\(m_B=m_{MgCl2}+m_{ZnCl2}=0,4.\left(24+72\right)+0,2.\left(65+71\right)=65,2\left(g\right)\)
\(n_{HCl}=2.0,4+2.0,2=1,2\left(mol\right)\)
Đổi : 200ml=0,2l
\(\rightarrow CM_{HCl}=\frac{1,2}{0,2}=6M\)