\(n_{HCl}=0,1.3=0,3\left(mol\right)\\ CaO+2HCl\xrightarrow[]{}CaCl_2+H_2O\\ CaCO_3+2HCl\xrightarrow[]{}CaCl_2+H_2O+CO_2\\ n_{CaO}=a;n_{CaCO_3}=b\\ \Rightarrow\left\{{}\begin{matrix}2a+2b=0,3\\56a+100b=11,7\end{matrix}\right.\\ \Rightarrow a=b=0,075\left(mol\right)\\ n_{CaCl_2}=n_{CaO}=n_{CaCO_3}=0,075mol\\ m_{CaCl_2}=\left(0,075+0,075\right).111=16,65\left(g\right)\)