Ta có: \(m_{Cl^-}=m_{muối}-m_{KL}=28,4\left(g\right)\)
\(\Rightarrow n_{Cl^-}=\dfrac{28,4}{35,5}=0,8\left(mol\right)=n_{HCl}\)
Bảo toàn Hidro: \(n_{H_2}=\dfrac{1}{2}n_{HCl}=0,4\left(mol\right)\) \(\Rightarrow V_{H_2}=0,4\cdot22,4=8,96\left(l\right)\)
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