Áp dụng tc dtsbn:
\(\dfrac{a}{3}=\dfrac{b}{5}=\dfrac{b-a}{5-3}=\dfrac{20}{2}=10\\ \Rightarrow\left\{{}\begin{matrix}a=30\\b=50\end{matrix}\right.\)
a; b tỉ lệ với 3; 5
\(\Rightarrow\) \(\dfrac{a}{3}=\dfrac{b}{5}=\dfrac{b-a}{5-3}=\dfrac{20}{2}=10\)
Ta có: \(\left\{{}\begin{matrix}\dfrac{a}{3}=10\Rightarrow a=10.3=30\\\dfrac{b}{5}=10\Rightarrow b=10.5=50\end{matrix}\right.\)