Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
gpt:
\(x^4-2x^3+x=\sqrt{(x^2-x).2}\)
\(x(5x^3+2)-2(\sqrt{2x+1}-1)=0\)
\(\sqrt{x+\frac{3}{x}}=\frac{x^2-7}{2x+2}\)
GPT
a) \(\sqrt{5x}-\sqrt{20x}+\sqrt{180x}-15=0\)
b) \(\frac{1}{2}\sqrt{x-1}-\frac{3}{2}\sqrt{9x-9}+24\sqrt{\frac{x-1}{64}=-17}\)
c)\(x-7\sqrt{x-3}+9=0\)
d) \(-5x+7\sqrt{x}+12=0\)
GPT
a) \(\sqrt{x}+\sqrt{x+1}=\frac{1}{\sqrt{x}}\)
b) \(\frac{x+3+2\sqrt{x^2-9}}{2x-6+\sqrt{x^2-9}}=\sqrt{2}\)
1)\(7\sqrt{3x-7}+\left(4x-7\right)\sqrt{7-x}=32\)
2)\(4x^2-11x+6=\left(x-1\right)\sqrt{2x^2-6x+6}\)
3)\(9+3\sqrt{x\left(3-2x\right)}=7\sqrt{x}+5\sqrt{3-2x}\)
4)\(\sqrt{2x^2+4x+7}=x^4+4x^3+3x^2-2x-7\)
5)\(\frac{6-2x}{\sqrt{5-x}}+\frac{6+2x}{\sqrt{5+x}}=\frac{8}{3}\)
6)\(2\left(5x-3\right)\sqrt{x+1}+\left(x+1\right)\sqrt{3-x}=3\left(5x+1\right)\)
7)\(\sqrt{7x+7}+\sqrt{7x-6}+2\sqrt{49x^2+7x-42}=181-14x\)
\(\left(\frac{2}{\sqrt{x}-2}+\frac{3}{2\sqrt{x}+1}-\frac{5\sqrt{x}-7}{2x-3\sqrt{x}-2}\right)\): \(\frac{2\sqrt{x}+3}{5x-10\sqrt{x}}\)(với x >0, x khác 4)
Cho A= \(\frac{\sqrt{x}}{\sqrt{x}+3}+\frac{2\sqrt{x}-3}{\sqrt{x}-3}-\frac{2x-\sqrt{x}-3}{x-9}\)và B=\(\frac{x+7}{\sqrt{x}}(x>0,x\ne9)\)
a) Rút gọn A
b) Tìm GTNN của \(S=\frac{1}{A}+B\)
B=\(\frac{x-\sqrt{x}}{x-\sqrt{4x}}+\frac{x-9}{2x-\sqrt{25x}-3}\frac{6x-7}{2x-\sqrt{9x}-2}\)
a) rút gọn
b)tìm x để B<1
Rút gọn
a, \(\left(3+\sqrt{5}\right)\sqrt{14-6\sqrt{5}}\)
b, \(\frac{2}{3+\sqrt{7}}\) + \(\frac{\sqrt{28}}{2}\) - 2
c, \(\frac{3}{3\sqrt{7}-6}-\frac{3}{3\sqrt{7}+6}\)
d, \(\left(\sqrt{3}+1\right)\sqrt{\frac{14-6\sqrt{3}}{5+\sqrt{3}}}\)
e, \(M=\frac{\sqrt{x}-1}{\sqrt{x}+3}-\frac{7\sqrt{x}-3}{9-x}-\frac{3\sqrt{x}-x}{\sqrt{x}-3}\)
tìm x biết
a)\(\frac{3\sqrt{x}-5}{2}-\frac{2\sqrt{x}-7}{3}+1=\sqrt{x}\)
b)\(\sqrt{9x^2+45}-\frac{1}{12}\sqrt{16x^2+80}+3\sqrt{\frac{x^2+5}{16}}-\frac{1}{4}\sqrt{\frac{25x^2+125}{9}}=9\)
