Question

gpt ẩn x sau

\(\frac{x-ab}{a+b}+\frac{x-ac}{a+c}+\frac{x-bc}{b+c}=a+b+c\)

Answer 1

pt \(\Rightarrow\frac{x}{a+b}+\frac{x}{a+c}+\frac{x}{b+c}=\left(\frac{ab}{a+b}+c\right)+\left(\frac{ac}{a+c}+b\right)+\left(\frac{bc}{b+c}+a\right)\)

\(\Rightarrow\left(\frac{1}{a+b}+\frac{1}{a+c}+\frac{1}{b+c}\right).x=\frac{ab+ac+bc}{a+b}+\frac{ac+ab+bc}{a+c}+\frac{bc+ab+ac}{b+c}\)

\(\Rightarrow\left(\frac{1}{a+b}+\frac{1}{a+c}+\frac{1}{b+c}\right).x=\left(ab+bc+ac\right)\left(\frac{1}{a+b}+\frac{1}{a+c}+\frac{1}{b+c}\right)\)

Nếu \(\frac{1}{a+b}+\frac{1}{a+c}+\frac{1}{b+c}\ne0\) => phương trình có 1 ngiệm x = ab + bc +ca

Nếu \(\frac{1}{a+b}+\frac{1}{a+c}+\frac{1}{b+c}=0\) => phương trình có vô số nghiệm

 

 

Answer 2

cảm ơn

Answer 3

thank you