tui giải khác không biết phải không =]]
=>4 \(\left(\sqrt{x+1}\right)^2\)- 4 \(\left(\sqrt{1-x}\right)^2\)+(3 - x) = 3\(\left(\sqrt{1-x}\right)^2\)
= >4(x+1) -4(1-x) + (3-x) = 3(1-x)
=>4x +4 -4 +4x +3 -x = 3 - 3x
=>10x = 0
=> x=0 => pt VN
gpt:
\(\sqrt{x}+\sqrt[4]{x\left(1-x\right)}+\sqrt[4]{\left(1-x\right)^3}=\sqrt{1-x}+\sqrt[4]{x^3}+\sqrt[4]{x^2\left(1-x\right)}\)
gpt\(\sqrt[4]{1-x^2}+\sqrt[4]{1+x}-\sqrt[4]{1-x}=3\)
Gpt: \(\sqrt{x-1}+\sqrt{x^3+x^2+x+1}=1+4\sqrt{x^4-1}\)
GPT: \(3.\sqrt{1-x^2}=4\sqrt{1+x}-4\sqrt{1-x}+\left(3-x\right)\)
gpt :
1, \(2\left(2\sqrt{1+x^2}-\sqrt{1-x^2}\right)-\sqrt{1-x^4}=3x^2+1\)
2, \(2\sqrt{1-x}+\sqrt{x+1}+3\sqrt{1-x^2}=3-x\)
gpt ( đặt ẩn phụ không hoàn toàn)
9, \(2\sqrt{1-x}+\sqrt{x+1}+3\sqrt{1-x^2}=3-x\)
10, \(4\sqrt{1-x}+3\sqrt{1-x^2}=x+6+5\sqrt{1+x}\).
gpt:
\(x^2-3x+1=-\frac{\sqrt{3}}{3}\sqrt{x^4+x^2+1}\)
GPT :
\(\sqrt[4]{x}+\sqrt{x}+\sqrt[4]{1-x}+\sqrt{1-x}=2\sqrt[4]{\frac{1}{2}}+2\sqrt{\frac{1}{2}}\)
GPT :
\(\sqrt[4]{x}+\sqrt{x}+\sqrt[4]{1-x}+\sqrt{1-x}=2\sqrt[4]{\frac{1}{2}}+2\sqrt{\frac{1}{2}}\)