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BS
17 tháng 1 2023 lúc 19:31

\(a,\dfrac{-4}{5}+\dfrac{2}{7}-\dfrac{1}{5}-\dfrac{9}{7}=\left(\dfrac{-4}{5}-\dfrac{1}{5}\right)+\left(\dfrac{2}{7}-\dfrac{9}{7}\right)=-1+\left(-1\right)=-2\)

\(b,\dfrac{1}{12}-\left(\dfrac{1}{2}+\dfrac{7}{12}\right)=\dfrac{1}{12}-\left(\dfrac{6}{12}+\dfrac{7}{12}\right)=\dfrac{1}{12}-\dfrac{13}{12}=\dfrac{-12}{12}=-1\)

\(c,\dfrac{-12}{5}-\left(\dfrac{3}{5}-\dfrac{1}{8}\right)=\dfrac{-12}{5}-\left(\dfrac{24}{40}-\dfrac{5}{40}\right)=\dfrac{-12}{5}-\dfrac{19}{40}=\dfrac{-96}{40}-\dfrac{16}{40}=\dfrac{-100}{40}=\dfrac{-5}{2}\)

\(d,\dfrac{-5}{7}-\left(\dfrac{-7}{6}+\dfrac{2}{7}\right)+\dfrac{7}{-6}=\dfrac{-5}{7}+\dfrac{7}{6}-\dfrac{2}{7}+\dfrac{-7}{6}=\left(\dfrac{-5}{7}-\dfrac{2}{7}\right)+\left(\dfrac{7}{6}+\dfrac{-7}{6}\right)=-1\)

\(e,\dfrac{-6}{5}-\dfrac{2}{7}+\dfrac{1}{5}-\dfrac{5}{7}=\left(\dfrac{-6}{5}+\dfrac{1}{5}\right)+\left(\dfrac{-2}{7}-\dfrac{5}{7}\right)=-1+\left(-1\right)=-2\)

Bình luận (1)
HH
17 tháng 1 2023 lúc 19:22
Bình luận (1)
H24
17 tháng 1 2023 lúc 19:29

\(a,-\dfrac{4}{5}+\dfrac{2}{7}-\dfrac{1}{5}-\dfrac{9}{7}\)

\(=\dfrac{2}{7}-\dfrac{9}{7}-\dfrac{4}{5}-\dfrac{1}{5}\)

\(=-\dfrac{7}{7}-\dfrac{5}{5}\)

\(=-1-1=-2\)

\(b,\dfrac{1}{12}-\left(\dfrac{1}{2}+\dfrac{7}{12}\right)\)

\(=\dfrac{1}{12}-\dfrac{7}{12}-\dfrac{1}{2}\)

\(=-\dfrac{6}{12}-\dfrac{1}{2}=-1\)

\(c,-\dfrac{12}{5}-\left(\dfrac{3}{5}-\dfrac{1}{8}\right)\)

\(=-\dfrac{12}{5}-\dfrac{3}{5}+\dfrac{1}{8}\)

\(=-\dfrac{15}{5}+\dfrac{1}{8}\)

\(=-3+\dfrac{1}{8}=-\dfrac{23}{8}\)

\(d,-\dfrac{5}{7}-\left(-\dfrac{7}{6}+\dfrac{2}{7}\right)+\dfrac{7}{-6}\)

=\(-\dfrac{5}{7}+\dfrac{7}{6}-\dfrac{2}{7}-\dfrac{7}{6}\)

\(=-\dfrac{5}{7}-\dfrac{2}{7}\)

\(=-\dfrac{7}{7}=-1\)

\(e.-\dfrac{6}{5}-\dfrac{2}{7}+\dfrac{1}{5}-\dfrac{5}{7}\)

\(=-\dfrac{6}{5}+\dfrac{1}{5}-\dfrac{2}{7}-\dfrac{5}{7}\)

\(=\dfrac{5}{5}-\dfrac{7}{7}\)

\(=1-1=0\)

Bình luận (3)

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