Question

giúp vs các pạn ơi

Answer 1

ĐKXĐ:\(x\ne-1\)

\(\dfrac{1-x}{x+1}-\dfrac{3+2x}{x+1}=0\\ \Leftrightarrow\dfrac{1-x-3-2x}{x+1}=0\\ \Rightarrow-3x-2=0\\ \Leftrightarrow-3x=2\\ \Leftrightarrow x=-\dfrac{2}{3}\left(tm\right)\)

Answer 2

đk : x khác -1 

\(\dfrac{1-x-3-2x}{x+1}=0\Leftrightarrow\dfrac{-3x-2}{x+1}=0\Rightarrow-3x-2=0\Leftrightarrow x=-\dfrac{2}{3}\)(tm) 

Answer 3

Đáp án: 2/3

HT