\(R_{tđ}=\dfrac{R_1.R_2}{R_1+R_2}==\dfrac{40.60}{40+60}=24\left(\Omega\right)\)
\(U=U_1=U_2=12V\)
\(\left\{{}\begin{matrix}I_1=\dfrac{U_1}{R_1}=\dfrac{12}{40}=0,3\left(A\right)\\I_2=\dfrac{U_2}{R_2}=\dfrac{12}{60}=0,2\left(A\right)\end{matrix}\right.\)
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