\(a,3x+17=-5\\ \Rightarrow3x=-22\\ \Rightarrow x=-\dfrac{22}{3}\\ b,\dfrac{-5}{8}=\dfrac{x}{16}\\ \Rightarrow x=\dfrac{-5}{8}.16\\ \Rightarrow x=-10\\ c,\dfrac{4}{9}+\dfrac{7}{3}:x=\dfrac{1}{5}\\ \Rightarrow\dfrac{7}{3}:x=-\dfrac{11}{45}\\ \Rightarrow x=-\dfrac{105}{11}\)
\(a)3.x+17=-5\)
\(3.x\) \(=\left(-5\right)-170=-22\)
\(x\) \(=\left(-22\right)\div3\)
\(x\) \(=\dfrac{-22}{3}\)
\(b)\dfrac{-5}{8}=\dfrac{x}{16}\)
\(\Rightarrow x=\dfrac{\left(-5\right)\times16}{8}=\dfrac{-80}{8}=-10\)
\(c)\dfrac{4}{9}+\dfrac{7}{3}:x=\dfrac{1}{5}\)
\(\dfrac{7}{3}:x=\dfrac{1}{5}-\dfrac{4}{9}\)
\(\dfrac{7}{3}:x=\dfrac{1}{5}+\left(\dfrac{-4}{9}\right)=\dfrac{9}{45}+\left(\dfrac{-20}{45}\right)=\dfrac{-11}{45}\)
\(x=\dfrac{7}{3}:\left(\dfrac{-11}{45}\right)=\dfrac{7}{3}\times\left(\dfrac{-45}{11}\right)\)
\(x=\dfrac{-315}{33}=\dfrac{-105}{11}\)
giúp mik vs ạk, mik cần gấp
