Question

giup tớ bài 3 a với

Answer 1

\(3\\ a,đkx\ge3\\ \sqrt{9\left(x-3\right)}-2.\dfrac{\sqrt{x-3}}{4}=5-2\sqrt{16\left(x-3\right)}\\ 3\sqrt{x-3}-\sqrt{x-3}-5+8\sqrt{x-3}=0\\ \sqrt{x-3}\left(3-1+8\right)=5\\ 10\sqrt{x-3}=5\\ \sqrt{x-3}=\dfrac{1}{2}\\ x-3=\dfrac{1}{4}\\ x=\dfrac{13}{4}\left(thoaman\right)\)

Answer 2

\(\sqrt{9x-27}-2\sqrt{\dfrac{x-3}{4}}=5-2\sqrt{16x-48}\)

<=> \(\sqrt{9(x-3)}-2\dfrac{\sqrt{x-3}}{2}=5-2\sqrt{16(x-3)}\)

<=> \(3\sqrt{x-3}-\sqrt{x-3}=5-8\sqrt{x-3}\)

<=> \(3\sqrt{x-3}-\sqrt{x-3}+8\sqrt{x-3}=5\)

<=> \(10\sqrt{x-3}=5\)

<=> \(\sqrt{x-3}=\dfrac{1}{2}\)

<=> \(x-3=\dfrac{1}{4}\)

<=> \(x=\dfrac{13}{4}\)

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