Question

giúp mn với mn tick đúng cho 

1,     -5²²- { -222 - [ -122 - ( 100 -5²²) + 2022 ] }

2,  tìm số nguyên n để : A = 2n² + n - 6 chia hết cho 2n + 1

 

Answer 1

Bài 1:

\(=-5^{22}+222+[-122-(100-5^{22})+2022]\)

\(=-5^{22}+222-122-100+5^{22}+2022\\ =(-5^{22}+5^{22})+(222-122-100)+2022\\ =0+0+2022=2022\)

Answer 2

Bài 2:

$2n^2+n-6\vdots 2n+1$

$\Rightarrow n(2n+1)-6\vdots 2n+1$

$\Rightarrow 6\vdots 2n+1$

$\Rightarrow 2n+1\in Ư(6)$

Mà $2n+1$ lẻ nên $2n+1\in \left\{\pm 1; \pm 3\right\}$

$\Rightarrow n\in \left\{0; -1; 1; -2\right\}$