\(\dfrac{3x-5}{8}-\dfrac{5x-4}{6}-\dfrac{6x+1}{10}=1\\ \Leftrightarrow\dfrac{15\left(3x-5\right)}{8.15}-\dfrac{20\left(5x-4\right)}{6.20}-\dfrac{12\left(6x+1\right)}{10.12}=1\\ \Leftrightarrow\dfrac{45x-75}{120}-\dfrac{100x-80}{120}-\dfrac{72x+12}{120}=1\\ \Leftrightarrow\dfrac{45x-75-100x+80-72x-12}{120}=1\\ \Leftrightarrow-127x-7=120\\ \Leftrightarrow-127x=127\\ \Leftrightarrow x=-1\)
Vậy `S={-1}`
Đúng 1
Bình luận (0)