P/s : Mik ko chắc đâu
Ta có :
\(B=3+9+27+...+177147+531441\)
\(\Rightarrow B=3^1+3^2+3^3+...+3^{11}+3^{12}\)
\(\Rightarrow3B=3^2+3^3+3^4+...+3^{12}+3^{13}\)
\(\Rightarrow3B-B=\left(3^2+3^3+3^4+...+3^{12}+3^{13}\right)-\left(3^1+3^2+3^3+...+3^{11}+3^{12}\right)\)
\(\Rightarrow2B=3^{13}-3^1\)
\(\Rightarrow B=\frac{3^{13}-3}{2}\)
\(\Rightarrow B=797160\)
Vậy \(B=797160\)
~ Ủng hộ nha
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