\(\left(x+3\right)^2=36\)
\(\Rightarrow\orbr{\begin{cases}x+3=6\\x+3=-6\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=3\\x=-9\end{cases}}\)
Vậy \(x\in\left\{3;-9\right\}\)
\(\left(x+5\right)^2=100\)
\(\Rightarrow\orbr{\begin{cases}x+5=10\\x+5=-10\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=5\\x=-15\end{cases}}\)
Vậy \(x\in\left\{5;-15\right\}\)
\(\left(2x-4\right)^2=0\)
\(\Rightarrow2x-4=0\)
\(\Rightarrow2\left(x-2\right)=0\)
\(\Rightarrow x-2=0\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
\(\left(x-1\right)^3=27\)
\(\Rightarrow\left(x-1\right)^3=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
Vậy \(x=4\)
Trả lời:
a, ( x + 3)2 = 36
=> x + 3 = 6 hoặc x + 3 = -6
=> x = 3 hoặc x = -9
Vậy x = 3; x = -9
b, ( x + 5 )2 = 100
=> x + 5 = 10 hoặc x + 5 = -10
=> x = 5 hoặc x = -15
Vậy x = 5; x = -15
c, ( 2x - 4 )2 = 0
=> 2x - 4 = 0
=> 2x = 4
=> x = 2
Vậy x = 2
d, ( x - 1 )3 = 27
=> x - 1 = 3
=> x = 4
Vậy x = 4