\(A=\dfrac{3a-2b}{2a-3b}=\dfrac{\dfrac{3a}{b}-\dfrac{2b}{b}}{\dfrac{2a}{b}-\dfrac{3b}{b}}=\dfrac{3.\dfrac{a}{b}-2}{2.\dfrac{a}{b}-3}=\dfrac{3.\dfrac{5}{6}-2}{2.\dfrac{5}{6}-3}=-\dfrac{3}{8}\)
Vậy \(A=-\dfrac{3}{8}\)
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