Question

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Answer 1

\(c,126-\left(x-1\right)^3=2021^0\\ \Rightarrow126-\left(x-1\right)^3=1\\ \Rightarrow\left(x-1\right)^3=125\\ \Rightarrow\left(x-1\right)^3=5^3\\ \Rightarrow x-1=5\\ \Rightarrow x=6\)

\(d,24-\left(x-1\right)^2=\left(-1\right)^{2021}\\ \Rightarrow d,24-\left(x-1\right)^2=-1\\ \Rightarrow\left(x-1\right)^2=25\\ \Rightarrow\left[{}\begin{matrix}x-1=-5\\x-1=5\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-4\\x=6\end{matrix}\right.\)

Answer 2

\(126-\left(x-1\right)^3=2021^0\)

\(126-\left(x-1\right)^3=1\)

\(\left(x-1\right)^3=125=5^3\)

\(x-1=5\)

\(x=6\)

Answer 3

Answer 4