\(5.\left(\dfrac{-1}{10}+\dfrac{7}{10}\right)-\dfrac{2}{13}.4\dfrac{1}{3}=\dfrac{5}{1}.\dfrac{3}{5}-\dfrac{2}{13}.\dfrac{13}{3}=\dfrac{3}{1}-\dfrac{2}{3}=\dfrac{9}{3}-\dfrac{2}{3}=\dfrac{7}{3}\)
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