\(15p=0,25h;720\left(kJ\right)=0,2\left(kWh\right)=200\left(Wh\right)\)
a. \(A=Pt\Rightarrow P=\dfrac{A}{t}=\dfrac{200}{0,25}=800\left(W\right)\)
b. \(\left[{}\begin{matrix}P=UI\Rightarrow I=\dfrac{P}{U}=\dfrac{800}{220}=\dfrac{40}{11}\left(A\right)\\R=\dfrac{U}{I}=\dfrac{220}{\dfrac{40}{11}}=60,5\left(\Omega\right)\end{matrix}\right.\)