\(a,1996+3992+5988+7948=19924\)
\(b,\dfrac{1988\times1996+1997\times11+1985}{1997\times1996-1995\times1996}=\dfrac{1988\times1996+1996\times11+11+1985}{1996\times\left(1997-1995\right)}=\dfrac{1996\times\left(1988+11\right)+1996}{1996\times2}=\dfrac{1996\times\left(1988+11+1\right)}{1996\times2}=\dfrac{1996\times2000}{1996\times2}=\dfrac{2000}{2}=1000\)
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